SOLUTION: A train leaves station M and travels west at 75 km/hr. Two hours later, a second train leaves the same station on a parallel track and travels west at 125 km/hr. Hor far from the s
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Question 932538: A train leaves station M and travels west at 75 km/hr. Two hours later, a second train leaves the same station on a parallel track and travels west at 125 km/hr. Hor far from the station M will the faster train catch the slower one? Answer by ptfile(81) (Show Source):
You can put this solution on YOUR website! Let t+2 = the time of the slower train
t = the time of the faster train
75kph= the speed of the slower train
125kph= the speed of the faster train
D=rt
Slower train
D=(75)(t+2)
D=75t+150
Faster train
D=(125)(t)
D=125t
How far from the station M will the faster train catch the slower one?
Distance of Slower train = Distance of faster train
75t+150 = 125t
150 = 50t
3 = t
The time it took the faster train to catch up with the slower train is 3 hours.
Check
75(3)+150 = 125(3)
225 + 150 = 375
375 = 375
