SOLUTION: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 2
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 2
Log On
Question 932280: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 200 miles apart. How fast is the east-bound cyclist going? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed east biker
y = speed west biker = x + 4
---
relative speed of the bikers:
x + y
x + x + 4
2x + 4
---
s = d/t
2x + 4 = 200/5
2x = 200/5 - 4
x = (200/5 - 4)/2
x = 18
y = x + 4
y = 18 + 4
y = 22
---
answer:
x = speed east biker = 18 mph
y = speed west biker = 22 mph
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php
