Question 932086: How would I go about solving 49x^2 + y^2 = 49 finding the center, vertices, co- vertices and foci?
Answer by MathLover1(20850)   (Show Source):
You can put this solution on YOUR website!  ........both sides divide by 
 => you have an ellipse; compare it to the standard form equation of an ellipse which is  (your example is an ellipse with Vertical Major Axis,because  ) where ( , ) is the center,  is semiminor axis length,  is semimajor axis length
Ellipses are actually very special cases of circles.
REMEMBER:
The right side of the equation must be  in order to be in standard form.
The point (,) is most commonly referred to as the CENTER.
In order to graph an ellipse, you need  points:
Right point ( ,)
Left point ( ,)
Top point (, )
Bottom point (, ).
in your case:
center at ( ,)
foci | ((, ) | (,  ))approx.((,  ) | (, ))
vertices | (, ) | ( )
semimajor axis length | 
semiminor axis length |
eccentricity | ( ) approx.
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