Question 931975: Two cruise ships leave Jamaica at 11 AM. At what time will the two ships be exactly 515.8 miles apart if the Princess Ann travels at 18.9 mph and the Queen Barbara travels at 22.4 mph and their new destinations causes the ships to diverge by 56.2 degrees.
I've been stuck on this for a while and don't even know where to begin with it, any help would be appreciated. T
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Two cruise ships leave Jamaica at 11 AM. At what time will the two ships be exactly 515.8 miles apart if the Princess Ann travels at 18.9 mph and the Queen Barbara travels at 22.4 mph and their new destinations causes the ships to diverge by 56.2 degrees.
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let t=amount of time ships will be 515.8 mi apart
distance=speed*travel time
use law of cosines: c^2=a^2+b^2-2abcosx, a=18.9t, b=22.4t, c=515.8, x=52.6˚
..
(515.8)^2=(18.9t)^2+(22.4t)^2-2(18.9t)(22.4t)cos(56.2˚)
266049.64=357.21t^2+501.76t^2-(2*18.9t*22.4t*cos(56.2)
266049.64=858.96t^2-471.03t^2
387.93t^2=266049.64
t^2=266049.64/387.93
t^2=685.82
t=26.19 hrs
What time will the two ships be exactly 515.8 miles apart? approx: 1:11 PM next day
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