Question 931950: How would I graph the following:
y= sin(x-pi/3)
amplitude= 1
period= 2 pi
phase shift = pi/3 right shift
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! How would I graph the following:
y= sin(x-pi/3)
amplitude= 1
period= 2 pi
phase shift = pi/3 right shift
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set up inequality of given sin function:
0≤(x-π/3)≤2π
add π/3 to each term
π/3≤x≤7π/3
1/4 period=2π/4=π/2=3π/6
...
coordinates of graph:
(2π/6,0),(5π/6,1),(8π/6,0),(11π/6,-1),(14/6,0)
or
(π/3,0),(5π/6,1),(4π/3,0),(11π/6,-1),(7/3,0)
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