SOLUTION: Tom ran from his house to a nearby park averaging only 0.1 mi/min. He ran downhill back to his house averaging 0.15 mi/min. His total running time was 50 minutes. How much time did
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Question 931756: Tom ran from his house to a nearby park averaging only 0.1 mi/min. He ran downhill back to his house averaging 0.15 mi/min. His total running time was 50 minutes. How much time did it take Tom to run from his house to the park? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = time from house to park
y = time from park to house
d = distance between house and park
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x + y = 50
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s = d/t
d = st
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d = 0.1x
d = 0.15y
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equate distances:
0.1x = 0.15y
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x + y = 50
0.1x = 0.15y
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put the system of linear equations into standard form
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x + y = 50
0.1x - 0.15y = 0
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = time from house to park = 30 minutes
y = time from park to house = 20 minutes
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