SOLUTION: A polygon has interior angles equal to x, x + 20, 2x, 2x - 10 and 50. a) How many sides does this polygon have? b) Work out the size of x. c) What us the size of each angle?

Algebra ->  Polygons -> SOLUTION: A polygon has interior angles equal to x, x + 20, 2x, 2x - 10 and 50. a) How many sides does this polygon have? b) Work out the size of x. c) What us the size of each angle?      Log On


   

Question 931715: A polygon has interior angles equal to x, x + 20, 2x, 2x - 10 and 50.
a) How many sides does this polygon have?
b) Work out the size of x.
c) What us the size of each angle?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a)5 angles, 5 sides.
b) Interior angles sum to %285-2%29%2A180=540
x%2Bx%2B20%2B2x%2B2x-10%2B50=540
6x%2B60=540
6x=480
x=80
c) The first angle is 80. I'll leave it to you to work out the others.