SOLUTION: solve algebraically x^2-4y^2=16 2y-x=2 please show steps, thank you

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Question 931665: solve algebraically
x^2-4y^2=16
2y-x=2
please show steps, thank you
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Previously Posted
2y-x=2 0r x = 2y-2
.....
x^2-4y^2=16
(2y-2)^2 - 4y^2 = 16
4y^2 - 8y + 4 - 4y^2 = 16
-8y + 4 = 16
-8y = 12
y = -12/8 = -3/2
x = -5 2%28-3%2F2%29+-+2
(-5, -1.5) the solution set for this System