SOLUTION: solve algebraically 4x^2+y^2=64 x^2+y^2=52 please show steps, thank you
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Question 931664
:
solve algebraically
4x^2+y^2=64
x^2+y^2=52
please show steps, thank you
Answer by
ewatrrr(24785)
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Previously Posted
4x^2+y^2=64
-1(x^2+y^2=52)
3x^2 = 12
x^2 = 4
x = ± 2
y = √48 = ±4√3
.......
(-2,4√3), (-2,-4√3), (2,4√3), (2,-4√3),