SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 93156: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(x+4)^2=(x+2)^2+76
X^2+8x+16=x^2+4x+4+76
8x-4x=80-16
4x=64
x=64/4
x=16 answer for the first number.
16+2=18 for the middle number .
16+4=20 for the highest number.
proof
20^2=18^2+76
400=324+76
400=400