Question 931465: When the first of three consecutive positive intergers is multiplied by the third, the result is 1 less than six times the second. find the three integers.
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! consecutive positive integers: (x-1), x, (x+1)
(x-1)(x+1) = 6x - 1
x^2 - 1 = 6x - 1
x^2 - 6x = 0
x(x - 6) = 0
The integers are positive, so x = 6 and the integers are 5, 6, and 7.
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