SOLUTION: Suppose sin x = −4/7 and 3π/2< x < 2π.
Find each of the following quantities:
sin (2x) =
sec (2x) =
cot(x) =
Please help
Thank you
Algebra ->
Trigonometry-basics
-> SOLUTION: Suppose sin x = −4/7 and 3π/2< x < 2π.
Find each of the following quantities:
sin (2x) =
sec (2x) =
cot(x) =
Please help
Thank you
Log On
Question 931430: Suppose sin x = −4/7 and 3π/2< x < 2π.
Find each of the following quantities:
sin (2x) =
sec (2x) =
cot(x) =
Please help
Thank you Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Suppose sin x = −4/7 and 3π/2< x < 2π.
Find each of the following quantities:
sin (2x) =
sec (2x) =
cot(x) =
***
Reference angle x is in quadrant IV where sin<0, cos>0
sinx=-4/7
cosx=√(1-sin^2(x))=√(1-(16/49))=√(33/49)=√(33)/7
..
sin(2x)=2sinxcosx=2*(-4/7)*(√(33)/7=-8√(33)/49
sec(2x)=1/cos(2x)=1/(1-2sin^2(x)=1/1-32/49=1/(17/49)=49/17
cotx=cosx/sinx=-√(33)/4
(