Question 931425: A rocket is launched from the top of a cliff that is 48 feet per second. The height, h, of the rocket after t seconds is given by the equation.
h=-16ft^2+48t+48. How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A rocket is launched from the top of a cliff that is 48 feet per second. The height, h, of the rocket after t seconds is given by the equation.
h=-16ft^2+48t+48. How long after the rocket is launched will it strike the ground?
-------------
That's not a rocket, it's a projectile.
It impacts when h = 0
-16ft^2+48t+48 = 0
Solve the quadratic for t.
|
|
|
