SOLUTION: Suppose sin(theta)= 1/3 and pie/2 is less than or equal to theta which is less than or equal to pie, find the exact values for each of the following
(sin(theta))^2 =
Cos(thet
Algebra ->
Trigonometry-basics
-> SOLUTION: Suppose sin(theta)= 1/3 and pie/2 is less than or equal to theta which is less than or equal to pie, find the exact values for each of the following
(sin(theta))^2 =
Cos(thet
Log On
Question 931272: Suppose sin(theta)= 1/3 and pie/2 is less than or equal to theta which is less than or equal to pie, find the exact values for each of the following
(sin(theta))^2 =
Cos(theta) =
Tan(theta) =
You can put this solution on YOUR website! Suppose sin(theta)= 1/3 and pie/2 is less than or equal to theta which is less than or equal to pie, find the exact values for each of the following
(sin(theta))^2 =
Cos(theta) =
Tan(theta) =
***
sinx=1/3 (π/2 ≤x ≤π)
Reference angle x is in quadrant II
cosx=√(1-sin^2(x))=√(1-1/9)=√(8/9)=-√8/3
..
(sin(theta))^2 =1/9
Cos(theta) =-√8/3
Tan(theta) =-1/√8=-3√8/8
(