SOLUTION: I REALLY NEED HELP WITH THIS ONE
1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 wait
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-> SOLUTION: I REALLY NEED HELP WITH THIS ONE
1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 wait
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1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 waiting times has a mean of 3.2 minutes with a standard deviation of 2.1 minutes. At α = 0.01, test the bus company's claim. Assume the pupulation is normally distributed.
A)
critical value t0 = -2.528; standardized test statistic ≈ -3.833; do not reject H0; There is not sufficient evidence to support the Metropolitan Bus Company's claim.
B)
None of the above
C)
critical value t0 = -2.539; standardized test statistic ≈ -0.287; do not reject H0; There is not sufficient evidence to reject the Metropolitan Bus Company's claim.
D)
critical value t0 = -2.539; standardized test statistic ≈ -3.833; reject H0; There is sufficient evidence to support the Metropolitan Bus Company's claim.
E)
critical value t0 = -2.528; standardized test statistic ≈- 3.833; reject H0; There is sufficient evidence to reject the Metropolitan Bus Company's claim.
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You can put this solution on YOUR website! H0: mu = 5min
H1: mu < 5min (Claim)
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sample of 20 waiting times has a mean of 3.2 minutes with a standard deviation of 2.1 minutes = -1.8/(3.2/sqrt(20)) = -3.883 rounded
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α = 0.01
invT(.01, 19) is -2.539
..........
-3.883 < -2.539
.......
Reject Ho, there is sufficient evidence to support the Metropolitan Bus Company's claim.
D)