SOLUTION: I REALLY NEED HELP WITH THIS ONE 1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 wait

Algebra ->  Probability-and-statistics -> SOLUTION: I REALLY NEED HELP WITH THIS ONE 1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 wait      Log On


   



Question 931181: I REALLY NEED HELP WITH THIS ONE

1. The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sample of 20 waiting times has a mean of 3.2 minutes with a standard deviation of 2.1 minutes. At α = 0.01, test the bus company's claim. Assume the pupulation is normally distributed.

A)
critical value t0 = -2.528; standardized test statistic ≈ -3.833; do not reject H0; There is not sufficient evidence to support the Metropolitan Bus Company's claim.

B)
None of the above

C)
critical value t0 = -2.539; standardized test statistic ≈ -0.287; do not reject H0; There is not sufficient evidence to reject the Metropolitan Bus Company's claim.

D)
critical value t0 = -2.539; standardized test statistic ≈ -3.833; reject H0; There is sufficient evidence to support the Metropolitan Bus Company's claim.

E)
critical value t0 = -2.528; standardized test statistic ≈- 3.833; reject H0; There is sufficient evidence to reject the Metropolitan Bus Company's claim.
THANKS

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
H0: mu = 5min
H1: mu < 5min (Claim)
......
sample of 20 waiting times has a mean of 3.2 minutes with a standard deviation of 2.1 minutes
t+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29 = -1.8/(3.2/sqrt(20)) = -3.883 rounded
......
α = 0.01
invT(.01, 19) is -2.539
..........
-3.883 < -2.539
.......
Reject Ho, there is sufficient evidence to support the Metropolitan Bus Company's claim.
D)