SOLUTION: Find two solutions of each equation. Give your answers in degrees (0° &#8804; &#952; < 360°) and in radians (0 &#8804; &#952; < 2&#960;). Do not use a calculator. (Do not e

Algebra ->  Trigonometry-basics -> SOLUTION: Find two solutions of each equation. Give your answers in degrees (0° &#8804; &#952; < 360°) and in radians (0 &#8804; &#952; < 2&#960;). Do not use a calculator. (Do not e      Log On


   



Question 931011: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not enter your answers with degree symbols. Enter your answers as comma-separated lists.)
csc θ = 2√3/3

degrees?
radians?

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not enter your answers with degree symbols. Enter your answers as comma-separated lists.)
csc θ = 2√3/3=2/Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not enter your answers with degree symbols. Enter your answers as comma-separated lists.)
***
csc θ = 2√3/3=2/√3
sin θ=1/csc θ=√3/2
θ=60,120 degrees or π/3, 2π/3 radians