SOLUTION: a random sample of 50 people was asked to keep a record of the amount of time spend watching tv in in a specified week. if the sample mean was 24.4 hours and the sample standard de
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Question 930949: a random sample of 50 people was asked to keep a record of the amount of time spend watching tv in in a specified week. if the sample mean was 24.4 hours and the sample standard deviation was 7.4 hours, give a 95% confidence interval estimate for the average time spent watching tv by all members of the population that week. what is the margin of error? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! sample mean was 24.4 hours and the sample standard deviation was 7.4 hours
ME = 1.96(7.4/sqrt(50) = 2.05 rounded
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24.4 ± 2 the confidence Interval estimate
(22.4, 26.4)
