SOLUTION: Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. 1. 4x^2+25y^2=100 2. x^2/16+y^2/25=1 3. 1/

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. 1. 4x^2+25y^2=100 2. x^2/16+y^2/25=1 3. 1/      Log On


   



Question 930815: Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph.
1. 4x^2+25y^2=100
2. x^2/16+y^2/25=1
3. 1/2x^2+1/8y^2=1/4
4. y^2=1-2x^2
5. X^2+4y^2=16

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center.
The foci distances from center: c = ±sqrt%28a%5E2-b%5E2%29 where a > b
eccentricity = c/a
.........
4x^2+25y^2=100
x%5E2%2F5%5E2+%2B+y%5E2%2F2%5E2+=+1 C(0,0)
V(5,0),V(-5,0) & V(0,2),V(0,-2)
c =√(25 - 4) = √(21)
eccentricity = √21/5

..........
x^2/16+y^2/25=1
x%5E2%2F4%5E2+%2B+y%5E2%2F5%5E2+=+1 C(0,0)
& V(4,0),V(-4,0) & V(0,5),V(0,-5)
c =√(25 - 16) = 3
eccentricity = 3/5

........
1/2x^2+1/8y^2=1/4
2x^2 + y^2/4 = 1
x%5E2%2F%28sqrt%281%2F2%29%29%5E2+%2B+y%5E2%2F+2%5E2+=+1
.........
y^2=1-2x^2
2x^2 + y^2 = 1
+x%5E2%2F%28sqrt%281%2F2%29%29%5E2+%2B+y%5E2%2F1%5E2+=+1
.......
X^2+4y^2=16
x%5E2%2F4%5E2+%2B+y%5E2%2F2%5E2+=+1