Question 930804: The speed of a moving sidewalk is 4 ft/sec. On the moving sidewalk a person can walk 99 feet forward in the same time it takes to walk 17 ft on a non-moving sidewalk in the opposite direction. At what rate would a person walk on a non-moving sidewalk?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x = walking speed on a non-moving sidewalk
y = speed of moving sidewalk = 4 ft/sec
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s = d/t
t = d/s
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moving sidewalk:
t = 99/(x + y)
t = 99/(x + 4)
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non-moving sidewalk:
t = 17/x
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equate times:
99/(x + 4) = 17/x
99/(x + 4) - 17/x = 0
99x/x(x + 4) - 17(x + 4)/x(x + 4) = 0
99x - 17(x + 4) = 0*x(x + 4)
99x - 17x - 4*17 = 0
82x - 68 = 0
82x = 68
x = 68/82
x = 0.829268292683 ft/sec
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check:
t = 99/(x + 4)
t = 99/(0.829268292683 + 4)
t = 20.5 sec
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t = 17/x
t = 17/0.829268292683
t = 20.5 sec
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answer:
x = walking speed on a non-moving sidewalk = 0.829268292683 ft/sec
x = walking speed on a non-moving sidewalk = 0.829 ft/sec * (1/5280 mile/ft) * (60*60 sec/hr)
x = walking speed on a non-moving sidewalk = 0.57 mph
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