SOLUTION: The length of a rectangular garden is 23 feet longer than its width. If the area of the garden is 288 square feet, what are the dimensions of the garden? A) First, write a quadr

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The length of a rectangular garden is 23 feet longer than its width. If the area of the garden is 288 square feet, what are the dimensions of the garden? A) First, write a quadr      Log On


   

Question 930750: The length of a rectangular garden is 23 feet longer than its width. If the area of the garden is 288 square feet, what are the dimensions of the garden?
A) First, write a quadratic equation in the from aw^2+bw+c=0 you can solve to answer the question given. Let w be the width of the garden.
Answer: The equation is __________.
Use the variable w.

B) Factor your equation from part [a] into the form (w+A)(w-B)=0 and enter the full factored equation below.
Answer: The factored equation is _________
Don't forget to include the right hand side of the equation and to use the correct variable.

C)Use your factored equation to find the length and width of the garden.
Length = _______ feet.
Width = ______ feet.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
w for width, L for length;
L=23+w.
288=wL
w%28w%2B23%29=288
w%28w%2B23%29-288=0
highlight%28w%5E2%2B23w-288=0%29.

Trying to factor the trinomial quadratic;
2,144;
3,96;
4,72;
6,48;
8,36;
9,32. Enough found.

highlight%28%28w-9%29%28w%2B32%29=0%29.

The sensible solution for w is w=9.