Question 930728: 1. The table below describes the smoking habits of a group of asthma sufferers.
Men / Nonsmoker 363 / Light Smoker 70/ Heavy Smoker 83/ Total 516
Women / Nonsmoker 385 / Light Smoker 88/ Heavy Smoker 90 / Total 563
Total / T Nonsmoker 748/ T Light Smoker 158 / T Heavy Smoker 173/ Total 1079
If one of the 1079 people is randomly selected, find the probability that the person chosen is a nonsmoker given that the person is a woman. Round to the nearest thousandth.
0.515
0.684
0.357
0.422
None of the above
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
| Nonsmoker | Light Smoker | Heavy Smoker | Total | | Men | 363 | 70 | 83 | 516 | | Women | 385 | 88 | 90 | 563 | | Total | 784 | 158 | 173 | 1079 |
It states that "given that the person is a woman". So we are 100% certain that this person selected is a woman.
We can cross out the other rows and just focus on the "women" row.
There are 563 women total. Of these women, 385 are nonsmokers
Divide: (# nonsmoking women)/(# total women) = 385/563 = 0.6838 which rounds to 0.684
The final answer is 0.684
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