SOLUTION: Half of the sum of two consecutive even numbers is at least 15 more than a quarter of the second number, find the least value of the numbers

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Question 930613: Half of the sum of two consecutive even numbers is at least 15 more than a quarter of the second number, find the least value of the numbers
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Let the two even numbers be n and n+2.  Then translating the
words,

expr%281%2F2%29%28n%5E%22%22%2B%28n%2B2%29%29%22%22%3E=%22%22expr%281%2F4%29%28n%2B2%29%2B15

Multiply both sides by 4 to clear of fractions:

4%2Aexpr%281%2F2%29%28n%5E%22%22%2B%28n%2B2%29%29%22%22%3E=%22%224%2Aexpr%281%2F4%29%28n%2B2%29%2B60

2%28n%5E%22%22%2B%28n%2B2%29%29%22%22%3E=%22%22n%2B2%7D%2B60%7D%7D%0D%0A%0D%0A%7B%7B%7B2%28n%2Bn%2B2%29%22%22%3E=%22%22n%2B2%2B60

2%282n%2B2%29%22%22%3E=%22%22n%2B62

4n%2B4%22%22%3E=%22%22n%2B62

4n%2B4%22%22%3E=%22%22n%2B62

3n%22%22%3E=%22%2258

n%22%22%3E=%22%2219%261%2F3

So the first even number n could be is 20

So the two consecutive even numbers are 20 and 22. 

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Checking:

We need to find half of the sum of the two 
consecutive even numbers.

Their sum is 20+22 or 42

Half their sum is 21

That must be at least 15 more than a quarter of the second number

A quarter of the second number is 22%2F4 or 5%261%2F2

Is 21 at least 15 more than 5%261%2F2?  Yes it is, for 21-5%261%2F2
is 15%261%2F2 so 21 is 15%261%2F2 more than 5%261%2F2.

So it checks.  Are 20 and 22 the least?

Let's try 18 and 20.

Their sum is 18+20 or 38

Half their sum is 19

That must be at least 15 more than a quarter of the second number

A quarter of the second number is 19%2F4 or 4%263%2F4

Is 19 at least 15 more than 4%263%2F4?  No it is't, for 19-4%263%2F4
is 14%261%2F4 so 19 is only 14%261%2F4 more than 4%263%2F4.

So it doesnt check.  So 20 and 22 are the least.

Answer 20 and 22.

Edwin