SOLUTION: Jose has $3.25 in nickels and dimes. If he has a total of 41 coins, how many of the coins are nickels?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Jose has $3.25 in nickels and dimes. If he has a total of 41 coins, how many of the coins are nickels?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 930595: Jose has $3.25 in nickels and dimes. If he has a total of 41 coins, how many of the coins are nickels?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x the number of dimes
....
10x + 5(41-x) = 325cents
x = (325 - 205)/5 = 24, the number of dimes. Nickels: 17 41-24
and...checking
240 + 85 = 325 0r $3.25