SOLUTION: Find the values of the trigonometric functions of &#952; of cot &#952; = 1/2, sin &#952; < 0? Solve for: I know that sin &#952; = -2/&#8730;(5) cos &#952; = -1/&#8730;(5) b

Algebra ->  Trigonometry-basics -> SOLUTION: Find the values of the trigonometric functions of &#952; of cot &#952; = 1/2, sin &#952; < 0? Solve for: I know that sin &#952; = -2/&#8730;(5) cos &#952; = -1/&#8730;(5) b      Log On


   



Question 930534: Find the values of the trigonometric functions of θ of cot θ = 1/2, sin θ < 0?
Solve for:
I know that
sin θ = -2/√(5)
cos θ = -1/√(5)
but how would I solve
cos θ =
sin (θ − 11π/6) =
tan (2θ + 3π/2)=
Thanks

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
cotθ = 1/2, sin θ < 0 , sinθ = -2/√5 = -2√5 /5 , cosθ = -1/√5 =- √5/5
...........
sin (11π/6) = -1/2 , cos (11π/6) = √3 /2
..... Plug and Play     
sin(x - y) = sin x cosy - cos x sin y
sin(θ − 11π/6) =
.......
tan 2θ = 2tanx / (1-tan^2x) = 4/(1-4) = -4/3
tan ( 3π/2) = cos/sin = 0
.........Plug and Play
tan(x + y) = tan x + tan y)/(1- tan x tan y
tan(2θ + 3π/2) = -4/3
..........
(cosx, sinx) Summary Unit Circle
.