SOLUTION: Travis made a business trip of 128 miles. He averaged 56 mph for the first part of the trip and 48 mph for the second part. If the trip took 2.5 hours, how long did he travel at
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-> SOLUTION: Travis made a business trip of 128 miles. He averaged 56 mph for the first part of the trip and 48 mph for the second part. If the trip took 2.5 hours, how long did he travel at
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Question 930522: Travis made a business trip of 128 miles. He averaged 56 mph for the first part of the trip and 48 mph for the second part. If the trip took 2.5 hours, how long did he travel at each rate? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = time traveled at 56 mph
y = time traveled at 48 mph
a = distance traveled at 56 mph
b = distance traveled at 56 mph
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s = d/t
d = st
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distance traveled at 56 mph:
a = 56x
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distance traveled at 56 mph:
b = 48y
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total distance:
a + b = 128
56x + 48y = 128
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total time:
x + y = 2.5
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put the system of linear equations into standard form
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56x + 48y = 128
x + y = 2.5
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = time traveled at 56 mph = 1 hour
y = time traveled at 48 mph = 1.5 hours
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