SOLUTION: a box contains nickels, dimes and pennies worth $5.56. the number of pennies is one more than twice the number of dimes, and there is an equal number of pennies and nickels. how ma
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Question 930483: a box contains nickels, dimes and pennies worth $5.56. the number of pennies is one more than twice the number of dimes, and there is an equal number of pennies and nickels. how many nickles are there in the box? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = pennies
y = nickels
z = dimes
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1x + 5y + 10z = 556
x = 2z + 1
x = y
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put the system of linear equations into standard form
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1x + 5y + 10z = 556
x - 2z = 1
x - y = 0
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = pennies = 51
y = nickels = 51
z = dimes = 25
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