Question 930433: Please help me solve this: Caitlin invested money in two mutual funds, a stock and balanced fund. She invested twice as much in the stock fund as in the balanced fund. At the end of one year, the stock fund earned the equivalent of 17% simple interest and the balanced fund earned 3.5%. If her total gain was $1125, determine how much she invested in each fund.
So far I've got the equations set up as 2x +x = 1125 and .17(2x) + .035x =???
Found 2 solutions by TimothyLamb, MathTherapy: Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = amount in stock fund
y = amount in balanced fund
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x = 2y
0.17x + 0.035y = 1125
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put the system of linear equations into standard form
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x - 2y = 0
0.17x + 0.035y = 1125
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = amount in stock fund = 6000
y = amount in balanced fund = 3000
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Answer by MathTherapy(10551) (Show Source):
You can put this solution on YOUR website! Please help me solve this: Caitlin invested money in two mutual funds, a stock and balanced fund. She invested twice as much in the stock fund as in the balanced fund. At the end of one year, the stock fund earned the equivalent of 17% simple interest and the balanced fund earned 3.5%. If her total gain was $1125, determine how much she invested in each fund.
So far I've got the equations set up as 2x +x = 1125 and .17(2x) + .035x =???
Your 1st equation is incorrect, so obviously, you wouldn’t and didn't have a sum for your 2nd equation
Do it like this:
Let amount invested in balanced fund, be B
Then amount invested in stock fund = 2B
Amount of interest earned on balanced-fund investment: .035B
Amount of interest earned on stock-fund investment: .17(2B), or .34B
Since total earned from both investments was $1,125, we get:
.035B + .34B = 1,125
.375B = 1,125
B, or amount invested in balanced fund = , or $
Amount invested in stock fund: 2(3,000), or $
You can do the check!!
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