Question 930400: Two buses leave a station at the same time and travel in opposite directions. One bus travels 11 mi/hr slower than the other. If the two buses are 702 mi apart after 6 hours, what is the rate of each bus?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x = speed of fast bus
y = speed of slow bus
y = x - 11
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relative speed of the two buses:
x + y
x + x - 11
2x - 11
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s = d/t
s = 702/6
2x - 11 = 702/6
2x = 702/6 + 11
x = (702/6 + 11)/2
x = 64
y = x - 11
y = 64 - 11
y = 53
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answer:
x = speed of fast bus = 64 mph
y = speed of slow bus = 53 mph
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