SOLUTION: Find the values of the trigonometric functions of θ if csc θ = 13/9
and θ is in Quadrant II
sin (θ) =
cos (θ) =
tan (θ) =
cot (&#
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-> SOLUTION: Find the values of the trigonometric functions of θ if csc θ = 13/9
and θ is in Quadrant II
sin (θ) =
cos (θ) =
tan (θ) =
cot (&#
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Question 930396: Find the values of the trigonometric functions of θ if csc θ = 13/9
and θ is in Quadrant II
sin (θ) =
cos (θ) =
tan (θ) =
cot (θ) =
sec (θ) =
Please explain, I know that sin must be 9/13? Found 2 solutions by Alan3354, ewatrrr:Answer by Alan3354(69443) (Show Source):
sin (θ) =
cos (θ) =
tan (θ) =
cot (θ) =
sec (θ) =
Please explain, I know that sin must be 9/13?
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cos = sqrt(1 - sin^2) = sqrt(1 - 81/169) = sqrt(88/169)
cos = (Q2 --> negative)
---
tan = sin/cos
cot = 1/tan
sec = 1/cos
You can put this solution on YOUR website! csc θ = 13/9 and Yes. sin θ = 9/13
what You are missing is Step
.......
θ is in Quadrant II
..........
cos θ = -2√22 / 13
tan θ = sin/cos = - 9 / 2√22
etc...