SOLUTION: solve algebraically for each system given below x^2+y^2=100 x+y=2

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Question 930365: solve algebraically for each system given below x^2+y^2=100 x+y=2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
From eq. 2,
x=2-y
x%5E2=4-4y%2By%5E2
Substituting into eq. 1,
4-4y%2By%5E2%2By%5E2=100
2y%5E2-4y-96=0
y%5E2-2y-48=0
%28y-8%29%28y%2B6%29=0
Two solutions:
y-8=0
y=8
Then,
x=2-8
x=-6
and
y%2B6=0
y=-6
Then,
x=2-%28-6%29%7D%7D%0D%0A%7B%7B%7Bx=2%2B6
x=8
(-6,8) and (8,-6)