SOLUTION: Dave and steve are 700 meters apart from each other on a straight path. Both start walking toward each other and meet each other after 7 minutes dave covers a distance of x meters

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Dave and steve are 700 meters apart from each other on a straight path. Both start walking toward each other and meet each other after 7 minutes dave covers a distance of x meters       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 930289: Dave and steve are 700 meters apart from each other on a straight path. Both start walking toward each other and meet each other after 7 minutes dave covers a distance of x meters in one minute, which is 20 meters less than the distance steve covers in a minute. Which of these equations can be used to find the rate at which steve and dave walk?
A. 7x -(7x+20)=700
B.7x + (7x+20 =700
C. 7x + (7x-20)=700
D.7x - 7(x-20) =700

Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Dave and steve are 700 meters apart from each other on a straight path. Both start walking toward each other and meet each other after 7 minutes
Dave covers a distance of x meters in one minute, which is 20 meters less than the distance steve covers in a minute. Which of these equations can be used to find the rate at which steve and dave walk?
Dave DATA:
rate = x meters/min ; time = 7 min ; distance = r*t = 7x meters
------------
Steve DATA:
rate = x+20 meters/min ; time = 7 min ; distance = r*t = 7(x+20) meters
----
Equation:
distance + distance = 700 meters
7x + 7(x+20) = 700
==============
cheers,
Stan H.
-----------------

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Dave and Steve are 700 meters apart from each other on a straight path.
Both start walking toward each other and meet each other after 7 minutes Dave covers a distance of x meters in one minute, which is 20 meters less than the distance Steve covers in a minute.
Which of these equations can be used to find the rate at which Steve and Dave walk?
:
I don't think any of these are right
The equation would be: 7x + 7(x-20) = 700
:
Confirm this by solving for x
7x + 7x - 140 = 700
14x = 840
x = 60 meters per minute is Steve's rate
then 40 meters/min is Dave's rate
Find the distance each traveled
7*60 = 420 m
7*40 = 280 m
------------
total 700m