Question 930129: A random sample has 61 values. The sample mean is 9.9 and the sample standard deviation is 2. Use a level of significance of a=0.01 to conduct a right-tailed test of the claim that the population mean is 9.2 ( i.e, H_0: u= 9.2, H_1: u>9.2).
A)Compute the sample test statistic t.
B) Do we reject or fail to reject H_0? Explain you reasoning.
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! A)
t = (xbar - mu)/(s/sqrt(n))
t = (9.9 - 9.2)/(2/sqrt(61))
t = 2.733587
The test statistic is approximately t = 2.733587
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B)
Use a calculator or table to get
P(t > 2.733587) = 0.0041
Note: the degrees of freedom is df = n-1 = 61-1 = 60
So the p-value is 0.0041
Notice how the p-value (0.0041) is smaller than the significance level (alpha = 0.01), so we reject the null hypothesis H0. We reject H0 whenever (pvalue) < (alpha).
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