SOLUTION: The number of viewers of American Idol has a mean of 32 million with a standard deviation of 6 million. Assume this distribution follows a normal distribution.
What is the
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-> SOLUTION: The number of viewers of American Idol has a mean of 32 million with a standard deviation of 6 million. Assume this distribution follows a normal distribution.
What is the
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Question 930098: The number of viewers of American Idol has a mean of 32 million with a standard deviation of 6 million. Assume this distribution follows a normal distribution.
What is the probability that next week's show will:
(a)
Have between 38 and 44 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
Probability
(b)
Have at least 23 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
Probability
(c)
Exceed 51 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
You can put this solution on YOUR website! mean = 32 million, SD = 6 million.
P(38 < x < 44) = P( 1 < z < 2) = normalcdf( 1 , 2) = .1359
P(x ≥ 23) = P( z > -9/6) = normalcdf(-9/6, 100)= .9332
P( x > 51) = P(z > 19/6) = normalcdf( 19/6, 100)= .00077
Using a TI calculator 0r similarly a Casio fx-115 ES plus