Question 930078: write an equation for the line that passes through the points (-2,2)and (2,-8)
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! y2 - y1
------- = slope
x2 - x1
(-2,2) and (2,-8)
-8 - 2
-------- = slope {substituted into slope formula}
2 - (-2)
-10
---- = slope {subtracted on top and bottom}
4
-5
--- = slope
2
Point-slope form is y - y1 = m(x - x1)
(-2,2) , slope = -5/2
y - 2 = (-5/2)[x - (-2)] {substituted into point-slope form}
-2y + 4 = 5(x + 2) {multiplied entire equation by -5 and simplified}
-2y + 4 = 5x + 10 {used distributive property}
-2y = 5x + 6 {subtracted 4 from each side}
y = (-5/2)x - 3 {divided each side by -2}
For more help from me, visit: www.algebrahouse.com
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