Question 929928: Two towns are 1250 miles apart. A group of hikers start from each town and walk the trail towards each other. They meet after a total hiking time of 200 hours. If one group travels 2.5 mile per hour faster than the other group, find the rate of each group.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x = speed of group A
y = speed of group B
y = 2.5x
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s = d/t
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relative speed of the two groups:
x + y = 1250/200
x + 2.5x = 1250/200
3.5x = 1250/200
x = (1250/200)/3.5
x = 1.785714285710000
y = 2.5x
y = 2.5*1.785714285710000
y = 4.464285714270000
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answer:
x = speed of group A = 1.79 mph
y = speed of group B = 4.46 mph
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