Question 929902: Find the equation of a parabola with a vertex of (-3,-2) and a point of (6,-3)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
..........
parabola with a vertex of (-3,-2) and a point of (6,-3)
y = a(x+3)^2 - 2
-3= a(9)^2 -2
-1/81 = a
y = (1/81)(x+3)^2 - 2
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