SOLUTION: Find 3 consecutive numbers of which 4/5 of the sum of the first and second equals the third number decreased by 1.

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Question 929802: Find 3 consecutive numbers of which 4/5 of the sum of the first and second equals the third number decreased by 1.
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let N-1,N, and N%2B1 be the consecutive integers.
.
.
.
%284%2F5%29%28%28N-1%29%2BN%29=%28N%2B1%29-1
%284%2F5%29%282N-1%29=N
4%282N-1%29=5N
8N-4=5N
3N=4
N=4%2F3
However, the assumption is that these are integers.
There is no solution.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
3 consecutive numbers: x, x+1, x+2
(4/5)(2x+1) = x+2
8/5x + 4/5 = x+2
%283%2F5%29x++=+6%2F5 |Multiplying thru by 5 so as all denominators = 1
3x = 6
x = 2
.........
The 3 consecutive numbers are: 2, 3, 4
And... checking
(4/5)(5) = 4