SOLUTION: A random sample of male nontraditional students at a University yields the following ages (in years): 52, 68, 22, 35, 30, 56, 39, 48. It is known that the ages are normally distrib

Algebra ->  Probability-and-statistics -> SOLUTION: A random sample of male nontraditional students at a University yields the following ages (in years): 52, 68, 22, 35, 30, 56, 39, 48. It is known that the ages are normally distrib      Log On


   

Question 929506: A random sample of male nontraditional students at a University yields the following ages (in years): 52, 68, 22, 35, 30, 56, 39, 48. It is known that the ages are normally distributed. For this sample, the mean is 43.75 and the standard deviation is 15.05. Which one of the following represents a 99% confidence interval for the mean age of all such students at the University?





A 43.75 ± 3.355(5.321)

B 43.75 ± 3.355(1.881)

C 43.75 ± 2.896(5.321)

D 43.75 ± 3.499(1.881)

E 43.75 ± 3.499(5.321)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
invT(.995,7) = 3.499
ME = 3.499(15.05/sqrt(8))
ME = 3.499(5.321)
E.