SOLUTION: give the focus, directrix, and axis for the parabola: y^2=-4x

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Question 929319: give the focus, directrix, and axis for the parabola: y^2=-4x
Answer by lwsshak3(11628) About Me  (Show Source):
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give the focus, directrix, and axis for the parabola: y^2=-4x
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y^2=-4x
This is an equation of a parabola that opens leftward with vertex at the origin
Its basic form of equation: (y-k)^2=4p(x-h), (h,k)=coordinates of the vertex.
vertex:(0,0)
axis of symmetry: x-axis or y=0
4p=4
p=1
focus: (-1,0) (p-distance to the left of vertex on the axis of symmetry)
directrix: x=1 (p-distance to the right of vertex on the axis of symmetry)