SOLUTION: a. In a binomial experiment with n = 300 and p = 0.50, and the probability that P-hat is
greater than 60%.
b. In a binomial experiment with n = 300 and p = 0.55, and the probabil
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-> SOLUTION: a. In a binomial experiment with n = 300 and p = 0.50, and the probability that P-hat is
greater than 60%.
b. In a binomial experiment with n = 300 and p = 0.55, and the probabil
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Question 929259: a. In a binomial experiment with n = 300 and p = 0.50, and the probability that P-hat is
greater than 60%.
b. In a binomial experiment with n = 300 and p = 0.55, and the probability that P-hat is
greater than 60%.
c. In a binomial experiment with n = 300 and p = 0.60, and the probability that P-hat is
greater than 60%. Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! a. P(phat > .60) = P(z > .10/sqrt(.50*.50/300)) = normalcdf(6.928, 100)
b. P(phat > .60) = P(z > .15/sqrt(.55*.45/300))= normalcdf(5.2223, 100)
c. P(phat > .60) = P(z > 0/sqrt(.60*.40/300)) = .50 0r 50%
.........
For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Area under the standard normal curve to the left of the particular z is P(z)
Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
