SOLUTION: A sparkling-water distributor wants to make up 500 gal of sparkling water to sell for $8.00 per gallon. She wants to mix three grades of water selling for $12.00, $2.00, and $4.50
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Question 928846: A sparkling-water distributor wants to make up 500 gal of sparkling water to sell for $8.00 per gallon. She wants to mix three grades of water selling for $12.00, $2.00, and $4.50 per gallon, respectively. She must use twice as much of the $4.50 water as the $2.00,water. How many gallons of each should she use? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = gallons of $2.00 water
y = gallons of $4.50 water
z = gallons of $12.00 water
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2.00x + 4.50y + 12.00z = 8.00*500
x + y + z = 500
y = 2x
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put the system of linear equations into standard form
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2.00x + 4.50y + 12.00z = 4000
x + y + z = 500
2x - y = 0
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = gallons of $2.00 water = 80
y = gallons of $4.50 water = 160
z = gallons of $12.00 water = 260
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