Question 928795: I don't know how to solve this! System of equations by the elimination method:
x/2 + y/8 = 3
x - y/4 = 0 Found 2 solutions by TimothyLamb, MathTherapy:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x/2 + y/8 = 3
x - y/4 = 0
---
put the system of linear equations into standard form
---
0.5x + 0.125y = 3
x - 0.25y = 0
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = 3
y = 12
---
now by elimination:
---
0.5x + 0.125y = 3
-0.5(x - 0.25y = 0)
---
0.5x + 0.125y = 3
-0.5x + 0.125y = 0
---
add the two equations:
---
0.25y = 3
y = 3/0.25
y = 12
---
0.5x + 0.125y = 3
0.5x = 3 - 0.125y
x = (3 - 0.125y)/0.5
x = (3 - 0.125*12)/0.5
x = 3
---
solution by elimination:
x = 3
y = 12
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
You can put this solution on YOUR website!
I don't know how to solve this! System of equations by the elimination method:
x/2 + y/8 = 3
x - y/4 = 0
______4x + y = 24 ------ Multiplying by LCD, 8 ------ eq (i) ______4x - y = 0 ------- Multiplying by LCD, 4 ------ eq (ii)
8x = 24 ------- Adding eqs (ii) & (i)
x = , or
4(3) - y = 0 ------- Substituting 3 for x in eq (ii)
12 - y = 0
- y = - 12
y = , or
