SOLUTION: 16. The amount of time it takes to recover physiologically from a certain kind of sudden noise is found to be normally distributed with a mean of 80 seconds and a standard deviati
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-> SOLUTION: 16. The amount of time it takes to recover physiologically from a certain kind of sudden noise is found to be normally distributed with a mean of 80 seconds and a standard deviati
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Question 928778: 16. The amount of time it takes to recover physiologically from a certain kind of sudden noise is found to be normally distributed with a mean of 80 seconds and a standard deviation of 10 seconds. Using the 50%–34%–14% figures, approximately what percentage of scores (on time to recover) will be:
Above 100?
Below 100?
Above 90?
Below 90?
Above 80?
Below 80?
Above 70?
Below 70?
Above 60?
Below 60?
You can put this solution on YOUR website! For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Area under the standard normal curve to the left of the particular z is P(z)
Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
.........
mean of 80 seconds and a standard deviation of 10 seconds
Using the 50%–34%(1sd)–14%(2sd) figures
Above 100: 50 - 48 = 2%
Below 100: 98%
Above 90: 50 -34 = 16%
Below 90: 84%
Above 80: 50%
Below 80: 50%
Above 70: 34 + 50 = 84%
Below 70: 16%
Above 60: 14 + 34 + 50 = 98%
Below 60: 2%
