SOLUTION: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it

Algebra ->  Trigonometry-basics -> SOLUTION: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it       Log On


   

Question 92873This question is from textbook Algebra and Trigonometry
: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period? This question is from textbook Algebra and Trigonometry

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period?
-------------
Period = k(length)^2
If P = 2 sec and length = 6, find "k".
2 = k (6)^2
k = 2/36
k = 1/18
EQUATION for this pendulum:
Period = (1/18)(length)^2
--------------
If the period is 1 second find the length:
1 = (1/18)(length)^2
length^2 = 18
length = 3sqrt(2) ft.
===========
Cheers,
Stan H.