SOLUTION: One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in 5 hours. How long would it take to fill the pool if only the slower

Algebra ->  Rate-of-work-word-problems -> SOLUTION: One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in 5 hours. How long would it take to fill the pool if only the slower      Log On


   

Question 928434: One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in 5 hours. How long would it take to fill the pool if only the slower pipe is used?
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
rate = job/time
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rate fast pipe:
a = 1/t
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rate slow pipe:
b = 1/(1.25t)
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rate together:
a + b = 1/t + 1/(1.25t) = 1/5
1/t + 1/(1.25t) = 1/5
1.25t/t(1.25t) + t/t(1.25t) = 1/5
1.25t + t = (1/5)t(1.25t)
2.25t = (1/5)t(1.25t)
2.25t/t = (1/5)t(1.25t)/t
2.25 = (1/5)(1.25t)
t = 2.25 / ( (1/5)*(1.25) )
t = 9
1.25t = 1.25*9
1.25t = 11.25
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answer:
using only the slow pipe takes 11 hours and 15 minutes
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