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Question 928171: Find the value of k so that the point (-2,10) is on the line y=kx-3k
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! m = slope
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use the point-slope form of the line with the given point (-2,10):
y - 10 = m(x + 2)
y = mx + 2m + 10
y = mx + (2m + 10)
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equate to the given linear form:
kx - 3k = mx + (2m + 10)
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equate "like" terms:
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equate the x terms:
mx = kx
m = k
k = m
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equate the constant terms:
-3k = (2m + 10)
k = (2m + 10)/-3
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equate the k expressions:
m = (2m + 10)/-3
-3m = 2m + 10
-5m = 10
m = -2
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answer:
k = -2
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