SOLUTION: a square having an area of 48 sq.m. is inscribed in a circle which is inscribed in a regular hexagon. compute the area of the circle, area of the regular hexagon and the perimeter
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-> SOLUTION: a square having an area of 48 sq.m. is inscribed in a circle which is inscribed in a regular hexagon. compute the area of the circle, area of the regular hexagon and the perimeter
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Question 928101: a square having an area of 48 sq.m. is inscribed in a circle which is inscribed in a regular hexagon. compute the area of the circle, area of the regular hexagon and the perimeter of the regular hexagon. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a square having an area of 48 sq.m. is inscribed in a circle which is inscribed in a regular hexagon. compute the area of the circle, area of the regular hexagon and the perimeter of the regular hexagon.
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The diameter of the circle is the diagonal of the square.
The radius is the apothem of the hexagon.
The side length of the hexagon = apothem*tan(30)*2
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Area of a regular polygon with n sides of length s = ns^2*cot(180/n)/4
Perimeter = 6s
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It's calculator work.
