Question 928052: Two factory plants are making TV panels. Yesterday, Plant A produced 6000 panels. Ten percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 6% ?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x = panels produced by plant A = 6000
y = panels produced by plant B = ?
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0.1x + 0.03y = 0.06(x + y)
0.1*6000 + 0.03y = 0.06(6000 + y)
600 + 0.03y = 0.06*6000 + 0.06y
0.06y - 0.03y = 600 - 360
0.03y = 600 - 360
y = (600 - 360)/0.03
y = 8000
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answer:
y = panels produced by plant B = 8000
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