SOLUTION: Two bicyclists leave a rest stop going in the same direction. Bicyclist A travels at 20 mph and bicyclist B travels at 15 mph. B leaves 3 hours before A. After how many miles will
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Question 928018: Two bicyclists leave a rest stop going in the same direction. Bicyclist A travels at 20 mph and bicyclist B travels at 15 mph. B leaves 3 hours before A. After how many miles will A catch up to B? Found 2 solutions by TimothyLamb, MathTherapy:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! s = d/t
d = st
t = d/s
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speed of A relative to B:
s = 20 - 15 = 5 mph
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distance traveled by B when A departs:
d = 15*3 = 45 miles
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time traveled by A when he catches B:
t = 45/5 = 9 hours
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distance traveled by A when he catches B:
d = 20*9 = 180 miles
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You can put this solution on YOUR website!
Two bicyclists leave a rest stop going in the same direction. Bicyclist A travels at 20 mph and bicyclist B travels at 15 mph. B leaves 3 hours before A. After how many miles will A catch up to B?
Let distance A travels to catch B, be D
Then:
3D = 4D - 180 ----- Multiplying by LCD, 60
3D – 4D = - 180
- D = - 180
D, or distance A travels to catch up to B = , or miles
