SOLUTION: If a and b are positive consecutive odd integers where b > a, which of the following is equal to b^2-a^2 (those stand for squared)

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: If a and b are positive consecutive odd integers where b > a, which of the following is equal to b^2-a^2 (those stand for squared)      Log On


   

Question 927984: If a and b are positive consecutive odd integers where b > a, which of the following is equal to b^2-a^2 (those stand for squared)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
If a=n then, b=n%2B2
So,
b%5E2-a%5E2=%28n%2B2%29%5E2-n%5E2
b%5E2-a%5E2=%28n%5E2%2B4n%2B4%29-n%5E2
b%5E2-a%5E2=4n%2B4
b%5E2-a%5E2=4%28n%2B1%29
b%5E2-a%5E2=4b